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  "body": "\n## Statement\n\nLet $(P, \\le)$ be a partially ordered set and let $S$ be a subset of $P$.\nIf $b$ and $b'$ are both [[suprema|0BTMQ04556]] of $S$, then $b = b'$.\n\n## Remarks\n\nProof: $b$ is an upper bound and $b'$ is a least upper bound, thus $b' \\le b$. In the same way $b \\le b'$, and antisymmetry gives $b = b'$.\nThe same argument shows that a set has at most one infimum.\n\n## Explanations\n\n### L1 human\n\nA set cannot have two different least upper bounds.\nIf it had two, each one would be at most the other one, so they would be equal.\n",
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  "msc": [
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  "name": "Uniqueness of the supremum",
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