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  "body": "\n## Statement\n\nLet $I$ be an interval and let $f \\colon I \\to \\mathbb{R}$ be continuous and [[strictly increasing|0TR9SR9FTB]].\nThen $J = f(I)$ is an interval, and the inverse function $f^{-1} \\colon J \\to I$ is continuous and strictly increasing.\n\n## Remarks\n\nThe set $J$ is an interval by the [[intermediate value theorem|00KAFBR32E]].\nThe inverse is strictly increasing and its image is the interval $I$. A monotone function whose image is an interval has no jumps, so $f^{-1}$ is continuous.\nThe same holds for strictly decreasing functions.\nThis gives the continuity of $n$-th roots, of the [[logarithm|0044CPHJBV]], and of the inverse trigonometric functions.\n\n## Explanations\n\n### L1 human\n\nThe graph of $f^{-1}$ is the graph of $f$ reflected in the line $y = x$.\nA rising unbroken graph stays rising and unbroken after the reflection.\n",
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  "msc": [
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  "name": "Continuity of the inverse of a strictly monotone continuous function",
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