{
  "aliases": null,
  "backlinks": [
    {
      "field": "uses",
      "target": "009TEMTQKH"
    },
    {
      "field": "uses",
      "target": "0110GBHPPB"
    },
    {
      "field": "uses",
      "target": "01JADB9VW5"
    },
    {
      "field": "uses",
      "target": "033KTKKRV6"
    },
    {
      "field": "uses",
      "target": "04JHQNNBFE"
    },
    {
      "field": "uses",
      "target": "05RN90E14Y"
    },
    {
      "field": "uses",
      "target": "0BFMR2FQ8B"
    },
    {
      "field": "uses",
      "target": "0EHWPWGHB2"
    },
    {
      "field": "uses",
      "target": "0FS972T0ZH"
    },
    {
      "field": "uses",
      "target": "0J87V9K1GE"
    },
    {
      "field": "uses",
      "target": "0KAMF19NV8"
    },
    {
      "field": "uses",
      "target": "0NNDQVJ54Q"
    },
    {
      "field": "uses",
      "target": "0PQQGFAWSH"
    },
    {
      "field": "uses",
      "target": "0R7JS3DP3W"
    },
    {
      "field": "uses",
      "target": "0SPBPW3K61"
    },
    {
      "field": "uses",
      "target": "0V4VB6MQDC"
    },
    {
      "field": "uses",
      "target": "0VRWZDWW6B"
    },
    {
      "field": "uses",
      "target": "0XN7KEVSSS"
    },
    {
      "field": "uses",
      "target": "0YRG241HQQ"
    }
  ],
  "body": "\n## Definition\n\nLet $n$ and $k$ be natural numbers.\nThe binomial coefficient $\\binom{n}{k}$, read \"$n$ choose $k$\", is the natural number defined by the recursion\n$$\\binom{n}{0} = 1, \\qquad \\binom{0}{k+1} = 0, \\qquad \\binom{n+1}{k+1} = \\binom{n}{k} + \\binom{n}{k+1}.$$\n\n## Remarks\n\nThe value $\\binom{n}{k}$ is the [[number of k-element subsets|0BFMR2FQ8B]] of an $n$-element set. Many texts take this as the definition.\nFor $k \u003e n$, $\\binom{n}{k} = 0$. For $k \\le n$, the [[factorial formula|033KTKKRV6]] gives $\\binom{n}{k} = \\frac{n!}{k!\\,(n-k)!}$.\nThe recursion is [[Pascal's rule|0YRG241HQQ]], and the values form [[Pascal's triangle|05DME4TZ3K]].\n\n## Explanations\n\n### L1 human\n\nThe number $\\binom{n}{k}$ tells how many ways there are to choose $k$ objects out of $n$ when the order does not matter.\nFor example, $\\binom{4}{2} = 6$: from $\\{1, 2, 3, 4\\}$ you can choose $12, 13, 14, 23, 24, 34$.\n",
  "commit": "6ac761d40018146541484a9e8b9eafd6ecc303dc",
  "front": {
    "defines": "0GBZM0MT0F",
    "kind": "definition",
    "msc": [
      "05A10"
    ],
    "name": "Binomial coefficient",
    "sources": [
      {
        "locator": "Definition and interpretations",
        "url": "https://en.wikipedia.org/wiki/Binomial_coefficient"
      }
    ],
    "tag": "092GEF38YD"
  },
  "kind": "definition",
  "link": "https://math2.tamnd.com/node/092GEF38YD/",
  "links": [
    {
      "field": "defines",
      "target": "0GBZM0MT0F"
    }
  ],
  "markdown": "https://math2.tamnd.com/node/092GEF38YD.md",
  "msc": [
    "05A10"
  ],
  "name": "Binomial coefficient",
  "prov": null,
  "role": "",
  "source": "https://github.com/tamnd/math2/blob/main/nodes/092/092GEF38YD.md",
  "status": null,
  "tag": "092GEF38YD",
  "uri": "m2://092GEF38YD",
  "url": "https://math2.tamnd.com/wiki/binomial-coefficient-definition/",
  "writing": {
    "tag": "092GEF38YD",
    "kind": "definition",
    "level": "W1",
    "next": [
      {
        "what": "edge instance_of in",
        "note": "one example",
        "have": 0,
        "want": 1
      },
      {
        "what": "edge not_instance_of in",
        "note": "one non-example that fails one clause",
        "have": 0,
        "want": 1
      }
    ]
  }
}
