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  "body": "\n## Statement\n\nLet $X$ be a [[topological space|0CNQXVBHCX]] and let $(Y, d_Y)$ be a [[complete metric space|08EWT7J0SC]].\nLet $C_b(X, Y)$ be the set of [[continuous maps|0SY9ECQ19Q]] $f \\colon X \\to Y$ whose image $f(X)$ is [[bounded|0P953MG05E]] in $Y$.\nFor $f, g \\in C_b(X, Y)$, let $d_\\infty(f, g) = \\sup_{x \\in X} d_Y(f(x), g(x))$, with $d_\\infty(f, g) = 0$ when $X$ is empty.\nThen $(C_b(X, Y), d_\\infty)$ is a complete metric space.\n\n## Remarks\n\nFor $Y = \\mathbb{R}$, the metric $d_\\infty$ is the [[uniform metric|06HE9J7DXF]], and it comes from the [[sup norm|0PARCKE8WP]].\nProof sketch: a Cauchy sequence $(f_n)$ in $d_\\infty$ is Cauchy at each point $x$, so it has a pointwise limit $f(x)$ in $Y$. The convergence is uniform, and a uniform limit of continuous maps is continuous. The limit is also bounded.\nFor a compact space $X$, each continuous map to $\\mathbb{R}$ is bounded, so $C(X, \\mathbb{R})$ is complete with the sup metric.\n\n## Explanations\n\n### L1 human\n\nIf continuous functions get closer and closer to each other uniformly, then they converge uniformly to a function.\nThe key point is that this limit function is again continuous, so the limit stays in the space.\n",
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