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  "body": "\n## Statement\n\nLet $V$ and $W$ be normed vector spaces over $\\mathbb{R}$ and let $A \\colon V \\to W$ be a bounded linear map.\nThen $A$ is Fréchet differentiable at each point $x \\in V$, and its [[Fréchet derivative|08EVNYZF42]] at $x$ is $A$ itself: $DA(x) = A$.\n\n## Remarks\n\nThe proof is one line: $A(x + h) - A(x) - A h = 0$ for each $h$, so the remainder is $0$.\nFor $V = \\mathbb{R}^n$ and $W = \\mathbb{R}^m$, each linear map is bounded. So the derivative of $x \\mapsto M x$, for an $m \\times n$ matrix $M$, is the linear map with matrix $M$ at each point.\nAn affine map $x \\mapsto A x + b$ has the same derivative $A$ at each point, because the derivative of a constant map is $0$.\n\n## Explanations\n\n### L1 human\n\nThe best linear approximation of a linear map is the map itself.\nThis is the analogue of the rule that the derivative of $x \\mapsto c x$ is the constant $c$.\n",
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