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  "body": "\n## Statement\n\nLet $K$ be a commutative ring and let $A$ be an $n \\times n$ matrix over $K$.\nIf one row of $A$ is zero, then $\\det A = 0$, where $\\det$ is the [[determinant|00KDZRW4C0]].\n\n## Remarks\n\nThis follows from linearity in that row: the zero row is $0$ times itself, so $\\det A = 0 \\cdot \\det A = 0$.\nThe same holds for a zero column.\n\n## Explanations\n\n### L1 human\n\nA zero row means that one edge of the box spanned by the rows has length zero.\nSuch a box has no volume.\nSo the determinant is zero.\n",
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