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  "body": "\n## Definition\n\nLet $B = [a_1, b_1] \\times [a_2, b_2] \\times [a_3, b_3]$ with $a_i \u003c b_i$, and let $f \\colon B \\to \\mathbb{R}$ be bounded.\nPartition each interval $[a_i, b_i]$, and let $B_1, \\dots, B_N$ be the resulting closed sub-boxes, with volumes $\\Delta V_1, \\dots, \\Delta V_N$.\nFor points $p_k \\in B_k$, the sum $S = \\sum_{k=1}^{N} f(p_k) \\, \\Delta V_k$ is a Riemann sum of $f$.\nThe function $f$ is Riemann integrable on $B$ if there is $I \\in \\mathbb{R}$ with this property. For each $\\varepsilon \u003e 0$, there is $\\delta \u003e 0$ with $|S - I| \u003c \\varepsilon$ for all Riemann sums whose sub-boxes have diameter less than $\\delta$.\nThen $I$ is the triple integral of $f$ over $B$, written $\\iiint_B f(x, y, z) \\, dV$.\n\n## Remarks\n\nThis is the case $n = 3$ of the multiple integral over a box. The case $n = 2$ is the [[double integral|0NKBMFC18R]].\nFor a bounded solid $E \\subseteq B$, the integral over $E$ is the integral over $B$ of $f$ times the indicator function of $E$. The volume of $E$ is $\\iiint_E 1 \\, dV$, when this integral exists.\nBy [[Fubini's theorem|0R0T1VWH5X]], for continuous $f$ the triple integral equals an iterated integral. For example, $\\iiint_{[0,1]^3} x y z \\, dV = (1/2)^3 = 1/8$.\n\n## Explanations\n\n### L1 human\n\nA triple integral adds up the values of $f$ over a solid, each weighted by the volume of a small piece.\nIf $f$ is a density, the triple integral is the total mass of the solid.\n",
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