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  "body": "\n## Statement\n\nLet $F$ be a field, let $V$ be a vector space over $F$, and let $T \\colon V \\to V$ be a linear map.\nLet $v_1, \\dots, v_k$ be [[eigenvectors|0N6960W0BV]] of $T$ for eigenvalues $\\lambda_1, \\dots, \\lambda_k$ that are pairwise distinct.\nThen $v_1, \\dots, v_k$ are [[linearly independent|0CRMGPAH83]].\n\n## Remarks\n\nThe proof is by induction on $k$: apply $T - \\lambda_k \\id_V$ to a linear relation, and the term of $v_k$ disappears.\nSo the sum of the eigenspaces of $T$ for distinct eigenvalues is a direct sum.\nIn particular, an endomorphism of an $n$-dimensional space has at most $n$ distinct eigenvalues.\n\n## Explanations\n\n### L1 human\n\nEigenvectors for different eigenvalues point in genuinely different directions.\nNone of them is a combination of the others.\nThis is the key fact behind diagonalisation.\n",
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