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  "body": "\n## Statement\n\nLet $a_0, \\dots, a_{n-1}$ be real numbers, and let $p(r) = r^n + a_{n-1} r^{n-1} + \\dots + a_0$ be the [[characteristic polynomial|0QDXMG46QW]] of the equation $y^{(n)} + a_{n-1} y^{(n-1)} + \\dots + a_0 y = 0$.\nLet $r$ be a real root of $p$ of multiplicity $m \\ge 1$.\nThen the $m$ functions $e^{r x}, x e^{r x}, \\dots, x^{m-1} e^{r x}$ are linearly independent solutions of the equation on $\\mathbb{R}$.\nIf all the roots of $p$ are real, the union of these families over the distinct roots of $p$ is a [[fundamental system|0H4KNNCHPY]].\n\n## Remarks\n\nFor order $2$: if $r$ is a double root of $r^2 + a_1 r + a_0$, the solutions are $(c_1 + c_2 x) e^{r x}$.\nExample: $y'' - 2 y' + y = 0$ has $p(r) = (r - 1)^2$, so its solutions are $(c_1 + c_2 x) e^{x}$.\nThe same result holds for complex roots, with complex solutions. For the real form, see [[complex conjugate roots|0BEZX8F2XW]].\n\n## Explanations\n\n### L1 human\n\nA double root gives only one exponential, but we need two solutions.\nThe extra solution is the exponential times $x$.\nA root of multiplicity $m$ gives the exponential times $1, x, \\dots, x^{m-1}$.\n",
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