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  "body": "\n## Statement\n\nLet $G$ be an [[abelian|082GHNPJ53]] [[group|G5S1M9]].\nThen $G$ is [[simple|0YMYMNQ0QZ]] if and only if $G$ is finite of prime order.\nIn that case, $G$ is [[cyclic|0KVGH0J5B3]], and $G \\cong \\mathbb{Z}/p\\mathbb{Z}$ for a prime number $p$.\n\n## Remarks\n\nIn an abelian group, each subgroup is normal, so a simple abelian group has no subgroup except $\\{e\\}$ and itself.\nThen $G = \\langle g \\rangle$ for each $g \\neq e$, so $G$ is cyclic; $\\mathbb{Z}$ is not simple, because $2\\mathbb{Z}$ is a proper nontrivial subgroup.\nA finite cyclic group of order $n$ has a subgroup of order $d$ for each divisor $d$ of $n$, so $n$ must be prime.\n\n## Explanations\n\n### L1 human\n\nIn an abelian group, all subgroups are normal.\nSo a simple abelian group has no subgroups at all except the trivial ones.\nOnly the groups of prime order have this property.\n",
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