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  "body": "\n## Statement\n\nLet $\\alpha_1, \\dots, \\alpha_n$ be distinct [[algebraic numbers|0MB4TGMXG6]].\nThen $e^{\\alpha_1}, \\dots, e^{\\alpha_n}$ are linearly independent over the field of algebraic numbers.\nThat is, if $\\beta_1, \\dots, \\beta_n$ are algebraic numbers with $\\beta_1 e^{\\alpha_1} + \\dots + \\beta_n e^{\\alpha_n} = 0$, then $\\beta_1 = \\dots = \\beta_n = 0$.\n\n## Remarks\n\nA consequence: $e^{\\alpha}$ is [[transcendental|079EGSD32Y]] for each nonzero algebraic number $\\alpha$. In particular, $e$ is transcendental.\nAnother consequence: $\\pi$ is transcendental. Otherwise $i\\pi$ would be algebraic, and $e^{i\\pi} + 1 = 0$ would contradict the theorem.\nSo the circle cannot be squared with ruler and compass.\n\n## History\n\nFerdinand von Lindemann proved in 1882 that $e^{\\alpha}$ is transcendental for each nonzero algebraic $\\alpha$.\nKarl Weierstrass proved the general statement in 1885.\n\n## Explanations\n\n### L1 human\n\nThe exponential function sends nonzero algebraic numbers to transcendental numbers.\nWith $\\alpha = 1$ this shows that $e$ is transcendental, and with Euler's formula it shows the same for $\\pi$.\n",
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