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  "body": "\n## Statement\n\nLet $a$, $b$, $c$ and $d$ be elements of a commutative ring. Then\n$$(a^2 + b^2)(c^2 + d^2) = (ac - bd)^2 + (ad + bc)^2 = (ac + bd)^2 + (ad - bc)^2.$$\n\n## Remarks\n\nSo the product of two sums of two squares is again a sum of two squares.\nFor example, $5 \\cdot 13 = 65$, and the identity gives $65 = 1^2 + 8^2 = 7^2 + 4^2$.\nFor complex numbers, the identity says $|z|^2 |w|^2 = |zw|^2$ with $z = a + bi$ and $w = c + di$.\nIt is a step in the proof of the [[sum of two squares theorem|04NPWJMA6H]].\n\n## History\n\nThe identity appears in the Arithmetica of Diophantus, of the third century.\nBrahmagupta found it again in the seventh century, and Fibonacci published it in Europe in 1225.\n\n## Explanations\n\n### L1 human\n\nIf two numbers are sums of two squares, then so is their product.\nYou can check the identity by expanding both sides: the cross terms $2abcd$ cancel.\n",
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