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  "body": "\n## Statement\n\nLet $p$ be an odd prime.\nThen\n$$\\left(\\frac{-1}{p}\\right) = (-1)^{(p-1)/2},$$\nwhere the left side is a [[Legendre symbol|01J8AMV9RS]].\n\n## Remarks\n\nSo $\\left(\\frac{-1}{p}\\right) = 1$ if $p \\equiv 1 \\pmod 4$, and $\\left(\\frac{-1}{p}\\right) = -1$ if $p \\equiv 3 \\pmod 4$.\nThe proof is [[Euler's criterion|0M7DEDKSYB]] with $a = -1$.\nFor example, $2^2 = 4 \\equiv -1 \\pmod 5$, but $-1$ is not a square modulo $7$.\n\n## Explanations\n\n### L1 human\n\nThe number $-1$ is a square modulo an odd prime $p$ exactly when $p$ leaves remainder $1$ on division by $4$.\nSo $-1$ is a square modulo $5$, $13$ and $17$, but not modulo $3$, $7$ and $11$.\n",
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  "msc": [
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  "name": "First supplement to quadratic reciprocity",
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