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  "body": "\n## Statement\n\nLet $(a_n)$ and $(b_n)$ be real sequences and let $L$ be a real number.\nAssume that $(b_n)$ is strictly increasing and that $b_n \\to +\\infty$ as $n \\to \\infty$.\nAssume that\n$$\\lim_{n \\to \\infty} \\frac{a_{n+1} - a_n}{b_{n+1} - b_n} = L.$$\nThen $a_n / b_n \\to L$ as $n \\to \\infty$.\n\n## Remarks\n\nThere is also a $0/0$ form. If $a_n \\to 0$, $b_n \\to 0$, $(b_n)$ is strictly decreasing and the quotient of the differences tends to $L$, then $a_n / b_n \\to L$.\nWith $b_n = n$ it gives the [[convergence of the Cesàro means|0RDRPBMNAC]].\nFor example, with $a_n = 1 + 2 + \\cdots + n$ and $b_n = n^2$, the quotient of differences is $(n+1)/(2n+1) \\to 1/2$, so $a_n / n^2 \\to 1/2$.\nIt is a discrete analogue of [[L'Hôpital's rule|0JWT4PPQ7B]].\n\n## History\n\nOtto Stolz proved the $\\infty/\\infty$ case in a book of 1885. Ernesto Cesàro gave it in an article of 1888.\n\n## Explanations\n\n### L1 human\n\nTo compare two sequences that grow without bound, it is enough to compare their steps.\nIf each step of $a_n$ is about $L$ times the step of $b_n$, then $a_n$ is about $L$ times $b_n$ in the long run.\n",
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