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  "body": "\n## Statement\n\nLet $F$ be a field and let $V$ be a finite-dimensional vector space over $F$, with two bases $\\mathcal{B}$ and $\\mathcal{B}'$.\nLet $P$ be the [[change of basis matrix|0MKRHZB3WS]] whose columns are the coordinate vectors of the vectors of $\\mathcal{B}'$ in $\\mathcal{B}$.\nLet $B$ be a bilinear form on $V$, with [[matrix|0QK6K857HS]] $M$ in $\\mathcal{B}$ and $M'$ in $\\mathcal{B}'$.\nThen\n$$M' = P^T M P.$$\n\n## Remarks\n\nTwo square matrices $M$ and $M'$ are *congruent* when $M' = P^T M P$ for an invertible matrix $P$.\nSo two matrices represent the same bilinear form in two bases if and only if they are congruent.\nCongruence keeps the rank and the symmetry of a matrix, but in general not its eigenvalues.\nCompare this with the rule $P^{-1} A P$ for the matrix of a linear map.\n\n## Explanations\n\n### L1 human\n\nWhen we change the basis, the matrix of a bilinear form changes by $P^T M P$.\nBoth vectors change coordinates, so $P$ appears twice.\nFor a linear map, the rule is $P^{-1} A P$ instead.\n",
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