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  "body": "\n## Definition\n\nLet $n \\ge 1$ and let $a_0, \\dots, a_n$ be real numbers with $a_n \\ne 0$.\nThe Cauchy–Euler equation with these coefficients is the [[linear differential equation|0PB7K8M7FG]]\n$$a_n x^n y^{(n)} + a_{n-1} x^{n-1} y^{(n-1)} + \\dots + a_1 x\\, y' + a_0\\, y = 0$$\nfor an unknown function $y$ on the interval $x \u003e 0$.\n\n## Remarks\n\nThe substitution $x = e^{t}$, $u(t) = y(e^t)$ changes it into a [[linear equation with constant coefficients|0A6PGTTP2A]] for $u$.\nFor $n = 2$, the trial solution $y = x^m$ gives the indicial equation $a_2 m (m - 1) + a_1 m + a_0 = 0$.\nFor order $2$: a double root $m$ gives the solutions $x^m$ and $x^m \\ln x$. Roots $\\alpha \\pm i \\beta$ with $\\beta \\ne 0$ give $x^\\alpha \\cos(\\beta \\ln x)$ and $x^\\alpha \\sin(\\beta \\ln x)$.\nExample: $x^2 y'' - 2 y = 0$ gives $m(m-1) - 2 = 0$, so $m = 2$ or $m = -1$, and the solutions are $c_1 x^2 + c_2 x^{-1}$.\n\n## Explanations\n\n### L1 human\n\nIn this equation, each derivative $y^{(k)}$ is multiplied by $x^k$.\nSo powers $x^m$ behave like exponentials do for constant coefficients: the equation becomes a polynomial equation in $m$.\n",
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