{
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  "body": "\n## Statement\n\nLet $R \u003e 0$, and let $B = \\{(x, y, z) \\in \\mathbb{R}^3 : x^2 + y^2 + z^2 \\le R^2\\}$.\nThen\n$$\\operatorname{vol}(B) = \\frac{4}{3} \\pi R^3.$$\n\n## Remarks\n\nIn [[spherical coordinates|05WKRC7HWT]], $\\operatorname{vol}(B) = \\int_0^{2\\pi} \\int_0^\\pi \\int_0^R \\rho^2 \\sin \\varphi \\, d\\rho \\, d\\varphi \\, d\\theta = 2\\pi \\cdot 2 \\cdot R^3 / 3$.\nBy slices, the cross-section at height $z$ is a disc of area $\\pi (R^2 - z^2)$, and $\\int_{-R}^{R} \\pi (R^2 - z^2) \\, dz = \\tfrac{4}{3} \\pi R^3$. This is [[Cavalieri's principle|0GTZ2F3PQY]].\nThis is the case $n = 3$ of the [[volume of a ball in R^n|00YH28R457]], since $\\Gamma(5/2) = \\tfrac{3}{4} \\sqrt{\\pi}$.\nArchimedes found this volume, by comparison with a cone and a cylinder.\n\n## Explanations\n\n### L1 human\n\nThe ball of radius $R$ fills two thirds of the cylinder of radius $R$ and height $2R$ around it, since that cylinder has volume $2 \\pi R^3$.\nAny of the standard methods of multiple integration gives the same value.\n",
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