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  "body": "\n## Definition\n\nLet $D \\subseteq \\mathbb{R}^2$ be a bounded [[Jordan measurable|0565DC8RMK]] closed set, and let $r \\colon D \\to \\mathbb{R}^3$ be a [[parametrised surface|05788J51WZ]] that is injective on the interior of $D$.\nThe surface area of $S = r(D)$ is\n$$\\operatorname{area}(S) = \\iint_D \\| r_u(u, v) \\times r_v(u, v) \\| \\, du \\, dv.$$\n\n## Remarks\n\nThe integrand is the length of the [[normal vector|0BJDQ2HBH1]]. It is the area of the parallelogram spanned by $r_u$ and $r_v$, which approximates the image of a small parameter rectangle.\nFor the graph $z = f(x, y)$ over $D$, the area is $\\iint_D \\sqrt{1 + f_x^2 + f_y^2} \\, dx \\, dy$.\nFor the unit sphere, $\\| r_\\varphi \\times r_\\theta \\| = \\sin \\varphi$, and the area is $\\int_0^{2\\pi} \\int_0^\\pi \\sin \\varphi \\, d\\varphi \\, d\\theta = 4\\pi$.\nThe value does not depend on the parametrisation. A piecewise smooth surface gets the sum of the areas of its pieces. Inscribed polyhedra do not give a good definition: the Schwarz lantern is a counterexample.\n\n## Explanations\n\n### L1 human\n\nTo find the area of a curved surface, cut the parameter domain into small rectangles.\nEach one maps to a small curved patch, which is nearly a parallelogram, and you add up the areas of these parallelograms.\n",
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