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  "body": "\n## Definition\n\nLet $c$ be a [[pole|0WPQYW8MTE]] of $f$.\nThe order of the pole $c$ is the unique integer $m \\ge 1$ with the following property. On some punctured disc $0 \u003c |z - c| \u003c \\delta$,\n$$f(z) = \\frac{g(z)}{(z - c)^m},$$\nwhere $g$ is [[holomorphic|0DG0Z72CQD]] on the disc $|z - c| \u003c \\delta$ and $g(c) \\neq 0$.\nA pole of order $1$ is a simple pole.\n\n## Remarks\n\nThe order of the pole of $f$ at $c$ is the [[order of the zero|064N002TX4]] of $1/f$ at $c$.\nIn the Laurent series $\\sum a_n (z - c)^n$ of $f$ at $c$, the order is $m$ if and only if $a_{-m} \\neq 0$ and $a_n = 0$ for each $n \u003c -m$.\nMany authors give a pole of order $m$ the signed order $-m$. Then zeros have positive order and poles have negative order.\nFor example, $\\frac{1}{\\sin^2 z}$ has a pole of order $2$ at each point $k\\pi$ with $k \\in \\mathbb{Z}$.\n\n## Explanations\n\n### L1 human\n\nThe order of a pole says how fast the function goes to infinity at the point.\nNear a pole of order $m$, the function behaves like a constant times $1/(z - c)^m$.\n",
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