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  "body": "\n## Proof\n\n1. Let $\\varepsilon \u003e 0$.\n2. Since $f$ is [[uniformly continuous|0Q4DR37DVE]], there is $\\delta \u003e 0$ with $\\abs{f(x) - f(y)} \u003c \\varepsilon$ for all $x, y \\in D$ with $\\abs{x - y} \u003c \\delta$.\n3. Since $(x_n)$ is a [[Cauchy sequence|0QZMTN5AXX]], there is $N$ with $\\abs{x_m - x_n} \u003c \\delta$ for all $m, n \\ge N$.\n4. Let $m, n \\ge N$. The points $x_m$ and $x_n$ lie in $D$ and satisfy $\\abs{x_m - x_n} \u003c \\delta$. So step 2 gives $\\abs{f(x_m) - f(x_n)} \u003c \\varepsilon$.\n5. Since $\\varepsilon \u003e 0$ was arbitrary, $(f(x_n))$ is a Cauchy sequence.\n\n## Idea\n\nUniform continuity turns \"inputs within $\\delta$\" into \"outputs within $\\varepsilon$\", with one $\\delta$ for all points. A Cauchy sequence eventually has all its terms within $\\delta$ of each other. So the images are eventually within $\\varepsilon$ of each other.\n",
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