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  "body": "\n## Definition\n\nLet $I \\subseteq \\R$ be an interval and let $\\Omega \\subseteq \\R^n$ be an open set.\nLet $F$ be a [[multivalued function|03CPD1HGF3]] that assigns to each $(t, x) \\in I \\times \\Omega$ a nonempty subset $F(t, x)$ of $\\R^n$.\nThe *differential inclusion* given by $F$ is the relation\n$$x'(t) \\in F(t, x(t)).$$\nA *solution* on a subinterval $J \\subseteq I$ is an [[absolutely continuous|ZT6F4C2YHK]] function $x \\colon J \\to \\Omega$ such that $x'(t) \\in F(t, x(t))$ for almost every $t \\in J$.\n\n## Remarks\n\nIf $F(t, x) = \\set{f(t, x)}$ for a function $f$, the solutions are the solutions of the [[ordinary differential equation|0NT64JV96A]] $x' = f(t, x)$ in the sense of Carathéodory.\nExample: for $F(t, x) = [-1, 1]$ on $\\R \\times \\R$, the function $x(t) = \\abs{t}$ is a solution, since it is absolutely continuous and $x'(t) = \\pm 1$ for every $t \\ne 0$.\nNon-example: $x(t) = 2t$ is not a solution of the same inclusion, because $x'(t) = 2 \\notin [-1, 1]$ at every $t$.\nAn equation with a discontinuous right side, such as $x' = -\\sgn x$, is often replaced by the inclusion $x' \\in -\\operatorname{Sgn}(x)$, where $\\operatorname{Sgn}(0) = [-1, 1]$; then $x \\equiv 0$ is a solution.\nLocal existence of solutions holds when the values $F(t, x)$ are nonempty, compact and convex and $F$ satisfies suitable [[upper hemicontinuity|XNMKX7H4FD]] and measurability conditions.\n",
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