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  "body": "\n## Definition\n\nLet $H$ be a complex [[Hilbert space|HM2HHE3J51]] and let $S \\colon H \\to H$ be a bounded linear operator.\nThe operator $S$ is *subnormal* when there are a Hilbert space $K \\supseteq H$, with $H$ closed in $K$, and a bounded normal operator $N \\colon K \\to K$ such that\n\n1. $N(H) \\subseteq H$, that is, $H$ is an [[invariant subspace|0ACX5QT8TE]] of $N$;\n2. $Nx = Sx$ for all $x \\in H$.\n\nSuch an $N$ is a *normal extension* of $S$.\n\n## Remarks\n\nExample: the unilateral shift $S$ on $\\ell^2(\\N)$ is subnormal.\nView $\\ell^2(\\N)$ as the sequences in $\\ell^2(\\Z)$ that vanish at negative indices, and let $N$ be the bilateral shift $(Nx)_n = x_{n-1}$, which is unitary, hence normal.\n$N$ maps sequences vanishing at negative indices to sequences of the same kind, and it agrees with $S$ there.\n\nNon-example: $S = \\begin{pmatrix} 0 \u0026 1 \\\\ 0 \u0026 0 \\end{pmatrix}$ on $\\C^2$ is not subnormal.\nA subnormal operator is hyponormal, that is $S^*S - SS^* \\ge 0$, but here $S^*S - SS^* = \\mathrm{diag}(-1, 1)$, which is not positive.\n\nA normal extension $N$ can be chosen minimal: $K$ is the smallest closed subspace containing $H$ and invariant under $N$ and $N^*$.\nThe minimal normal extension is unique up to unitary equivalence.\n",
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