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  "body": "\n## Statement\n\nLet $A \\subseteq B$ be [[integral domains|0QVD7WBFGN]] with $B$ [[integral over|B7X0KFY1S1]] $A$.\nThen $A$ is a [[field|04C5ZBG1WT]] if and only if $B$ is a field.\n\n## Remarks\n\nSuppose $A$ is a field and let $b \\in B$ be nonzero.\nTake a monic relation $b^n + a_{n-1} b^{n-1} + \\cdots + a_0 = 0$ of least degree; since $B$ is a domain, $a_0 \\ne 0$.\nThen $b^{-1} = -a_0^{-1}(b^{n-1} + a_{n-1} b^{n-2} + \\cdots + a_1)$ lies in $B$.\nConversely, suppose $B$ is a field and let $a \\in A$ be nonzero.\nThen $a^{-1} \\in B$ is integral over $A$, say $a^{-m} + c_{m-1} a^{-m+1} + \\cdots + c_0 = 0$, and multiplying by $a^{m-1}$ gives $a^{-1} = -(c_{m-1} + c_{m-2} a + \\cdots + c_0 a^{m-1}) \\in A$.\n\nExample: $\\Q \\subseteq \\Q(\\sqrt{2})$ is integral and both are fields; $\\Z \\subseteq \\Z[i]$ is integral and neither is a field.\n\nThe hypothesis that $B$ is a domain is needed for \"$A$ field implies $B$ field\": the ring $k[x]/(x^2)$ is integral over the field $k$, but it is not a field.\n\n## Explanations\n\n### L1 human\n\nIn an integral extension of domains, the small ring is a field exactly when the big ring is.\nSo integral extensions cannot turn a non-field into a field, nor the reverse.\n\n### L2 human\n\nThis is the step that links maximal ideals across an integral extension: for a prime $\\mathfrak{q}$ of $B$, apply it to $A/(\\mathfrak{q} \\cap A) \\subseteq B/\\mathfrak{q}$.\nIt gives that $\\mathfrak{q}$ is maximal if and only if $\\mathfrak{q} \\cap A$ is maximal, and it is used in the proofs of [[lying over|YZ97GKYY3P]], [[incomparability|Q2XBHJ96GV]] and [[Zariski's lemma|YBJ2VQHFDQ]].\n",
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