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  "body": "\n## Definition\n\nLet $(\\Omega, \\mathcal{F}, P)$ be a [[probability space|0NFPJVJJHX]] and let $\\mathcal{G} \\subseteq \\mathcal{F}$ be a sub-[[σ-algebra|0SV8K0TDGY]].\nA *regular conditional probability* given $\\mathcal{G}$ is a map $\\nu \\colon \\Omega \\times \\mathcal{F} \\to [0, 1]$ such that:\n\n1. for each $\\omega \\in \\Omega$, the map $A \\mapsto \\nu(\\omega, A)$ is a [[probability measure|059TJN0NZ1]] on $(\\Omega, \\mathcal{F})$;\n2. for each $A \\in \\mathcal{F}$, the map $\\omega \\mapsto \\nu(\\omega, A)$ is $\\mathcal{G}$-measurable;\n3. for each $A \\in \\mathcal{F}$ and each $B \\in \\mathcal{G}$, $\\int_B \\nu(\\omega, A) \\, P(d\\omega) = P(A \\cap B)$.\n\n## Remarks\n\nClauses 2 and 3 say that $\\nu(\\cdot, A)$ is a version of the [[conditional probability|0990W5PN13]] $P(A \\mid \\mathcal{G}) = E[\\mathbf{1}_A \\mid \\mathcal{G}]$ for each $A$.\nThen $E[Z \\mid \\mathcal{G}](\\omega) = \\int Z(\\omega') \\, \\nu(\\omega, d\\omega')$ almost surely for every integrable $Z$.\nA regular conditional probability exists when $(\\Omega, \\mathcal{F})$ is a standard Borel space, for example a [[Polish space|584GXXY73M]] with its Borel σ-algebra.\nIt is then unique up to a $P$-null set of $\\omega$.\nIt need not exist in general.\nA related notion is the regular conditional distribution of a random variable $Y$ given $X$.\nIt is a [[Markov kernel|2AVNDP8BJP]] $\\kappa$ with $P(X \\in A, Y \\in B) = \\int_A \\kappa(x, B) \\, P_X(dx)$.\nIt exists whenever $Y$ takes values in a standard Borel space.\nExample: let $\\Omega = [0, 1]^2$ with Lebesgue measure, and let $\\mathcal{G}$ be generated by the first coordinate. Then $\\nu((x, y), A) = \\lambda(\\set{y' : (x, y') \\in A})$, with $\\lambda$ the Lebesgue measure on $[0, 1]$, is a regular conditional probability; clause 3 is [[Fubini's theorem|0R0T1VWH5X]].\nNon-example: if $\\mathcal{G} = \\set{\\emptyset, \\Omega}$ and $0 \u003c P(A) \u003c 1$ for some $A$, then $\\nu(\\omega, A) = \\mathbf{1}_A(\\omega)$ satisfies clause 1 but fails clause 2, since $\\mathbf{1}_A$ is not constant.\n",
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