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  "body": "\n## Definition\n\nLet $H$ be a complex [[Hilbert space|HM2HHE3J51]] and let $T \\colon H \\to H$ be a bounded linear operator with [[adjoint|6HSJBJ8TTQ]] $T^*$.\nThe operator $T$ is *hyponormal* when $T^*T - TT^*$ is a [[positive operator|77020CY5ZW]], that is,\n$$\\ip{(T^*T - TT^*)x}{x} \\ge 0 \\quad \\text{for all } x \\in H.$$\n\n## Remarks\n\nExample: for the unilateral shift $S(x_0, x_1, \\ldots) = (0, x_0, x_1, \\ldots)$ on $\\ell^2(\\N)$, one has $S^*S = I$ and $SS^*$ is the projection onto the vectors with $x_0 = 0$.\nSo $S^*S - SS^*$ is the projection onto the first coordinate, which is positive; $S$ is hyponormal.\n\nNon-example: the backward shift $S^*$ gives $(S^*)^* S^* - S^*(S^*)^* = SS^* - S^*S$, the negative of that projection, and $\\ip{(SS^* - S^*S)e_0}{e_0} = -1 \u003c 0$ for $e_0 = (1, 0, 0, \\ldots)$.\n\nEquivalent form: $T$ is hyponormal if and only if $\\norm{T^*x} \\le \\norm{Tx}$ for all $x \\in H$, since $\\ip{(T^*T - TT^*)x}{x} = \\norm{Tx}^2 - \\norm{T^*x}^2$.\nThe operator $T$ is normal exactly when both $T$ and $T^*$ are hyponormal.\n",
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