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  "body": "\n## Definition\n\nLet $H$ be a complex [[Hilbert space|HM2HHE3J51]], and let $A$ be a [[symmetric operator|H971WGMV6C]] on $H$ with dense domain and [[adjoint|86B7HF79PQ]] $A^*$.\nThe *deficiency subspaces* of $A$ are the closed subspaces\n$$K_+ = \\ker(A^* - iI), \\qquad K_- = \\ker(A^* + iI)$$\nof $H$, where $\\ker$ denotes the [[kernel|0S23E6YE83]].\nThe *deficiency indices* of $A$ are the [[Hilbert dimensions|40SV748R64]] $n_+ = \\dim K_+$ and $n_- = \\dim K_-$, which are cardinal numbers, possibly infinite.\n\n## Remarks\n\nEquivalently, $K_\\pm$ is the orthogonal complement of the [[image|0WSFKKT6FF]] of $A \\pm iI$.\nSome authors exchange the names of $K_+$ and $K_-$; the pair $(n_+, n_-)$ is then reversed.\nThe operator $A$ is [[essentially self-adjoint|DT49GKR9AS]] if and only if $n_+ = n_- = 0$.\nExample: on $L^2([0,1])$, let $A = -i \\, d/dx$ on the smooth functions with compact support in $(0,1)$.\nThen $A^*$ is $-i \\, d/dx$ on the Sobolev space $H^1([0,1])$, and $A^* u = \\pm i u$ means $u' = \\mp u$.\nSo $K_+$ is spanned by $e^{-x}$ and $K_-$ by $e^{x}$, and $(n_+, n_-) = (1, 1)$.\nExample with unequal indices: on $L^2([0, \\infty))$, the same construction gives $K_+$ spanned by $e^{-x}$, while $e^{x}$ is not square integrable, so $(n_+, n_-) = (1, 0)$.\nNon-example: the deficiency indices are not defined for an operator that is not densely defined, because then the adjoint is not a well-defined operator.\n",
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