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  "body": "\n## Definition\n\nLet $X$ be a [[compact|0TVJZYB6SH]] [[Hausdorff space|0S1FJ8VEX9]], and let $C(X)$ be the algebra of [[continuous|0X3WGX95FE]] functions $X \\to \\C$ with the sup norm $\\norm{f}_\\infty = \\max_{x \\in X} \\abs{f(x)}$.\nA *uniform algebra* on $X$ is a subalgebra $A \\subseteq C(X)$ such that:\n\n1. $A$ is closed in $C(X)$ for the sup norm, that is, under [[uniform convergence|08VZ57PT26]];\n2. $A$ contains the constant functions;\n3. $A$ separates the points of $X$: for $x \\ne y$ in $X$ there is $f \\in A$ with $f(x) \\ne f(y)$.\n\n## Remarks\n\nA uniform algebra is a commutative unital Banach algebra with $\\norm{f^2} = \\norm{f}^2$ for all $f$.\nConversely, a commutative unital complex Banach algebra with $\\norm{a^2} = \\norm{a}^2$ for all $a$ is isometrically isomorphic, through the Gelfand transform, to a uniform algebra on its character space.\n\nExample: the disc algebra $A(\\mathbb{D})$ on the closed unit disc $X = \\overline{\\mathbb{D}}$, the continuous functions on $X$ that are holomorphic in the open disc.\nIt is a subalgebra; it is closed because [[uniform limits of holomorphic functions are holomorphic|0431RN0R1N]]; it contains the constants; and $f(z) = z$ separates points.\n\nNon-example: on $X = [0, 1]$, let $A = \\set{f \\in C([0,1]) : f(0) = f(1)}$.\nIt is a closed subalgebra containing the constants, but no $f \\in A$ distinguishes $0$ from $1$, so clause 3 fails.\n\nBy the [[Stone–Weierstrass theorem|1P8D3MK79H]], a uniform algebra on $X$ that is closed under complex conjugation equals $C(X)$.\n",
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