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  "body": "\n## Problem\n\nIn 10 years, the father will be twice as old as his son.\n\n**Equivalent equation**\n\n$$\\begin{aligned} y + 10 \u0026= 2 \\times (x + 10)\\\\ y \u0026= 2 \\times (x + 10) - 10 \u0026\u0026 \\text{Subtract 10 from both sides}\\\\ y \u0026= 2x + 20 - 10 \u0026\u0026 \\text{Multiple out brackets}\\\\ y \u0026= 2x + 10 \u0026\u0026 \\text{Simplify} \\end{aligned}$$\n\nNow there are two related linear equations, each with two unknowns, which enables the production of a linear equation with just one variable, by subtracting one from the other (called the elimination method):\n\n$$\\begin{cases} y = x + 22 \u0026 \\text{First equation}\\\\ y = 2x + 10 \u0026 \\text{Second equation} \\end{cases}$$\n\n$$\\begin{aligned} \u0026\u0026\u0026\\text{Subtract the first equation from}\\\\ (y - y) \u0026= (2x - x) +10 - 22 \u0026\u0026 \\text{the second in order to remove } y\\\\ 0 \u0026= x - 12 \u0026\u0026 \\text{Simplify}\\\\ 12 \u0026= x \u0026\u0026 \\text{Add 12 to both sides}\\\\ x \u0026= 12 \u0026\u0026 \\text{Rearrange} \\end{aligned}$$\n\nIn other words, the son is aged 12, and since the father 22 years older, he must be 34. In 10 years, the son will be 22, and the father will be twice his age, 44. This problem is illustrated on the associated plot of the equations.\n\nFor other ways to solve this kind of equations, see below, **System of linear equations**.\n",
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