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  "body": "\n## Problem\n\nLet $(m_n)_{n \\ge 0}$ be a [[sequence|0G9EKM0E15]] of real numbers.\nDecide whether there is a positive Borel [[measure|PR11BZQQPG]] $\\mu$ on the closed interval $[0, 1]$ such that\n$$m_n = \\int_{[0,1]} x^n \\, d\\mu(x) \\quad \\text{for all } n \\ge 0.$$\nThe numbers $m_n$ are then the [[moments|01XAHPADBA]] of $\\mu$.\n\n## Remarks\n\nThe problem is solved.\nWrite $(\\Delta m)_n = m_{n+1} - m_n$ for the difference operator.\nHausdorff proved that such a measure exists if and only if the sequence is completely monotone, that is,\n$$(-1)^k (\\Delta^k m)_n \\ge 0 \\quad \\text{for all } n, k \\ge 0.$$\nWhen the measure exists, it is unique.\nUniqueness holds because polynomials are dense in the continuous functions on $[0, 1]$ by the Weierstrass approximation theorem.\nFor example, $m_n = 1/(n + 1)$ is the moment sequence of Lebesgue measure on $[0, 1]$.\n\n## Explanations\n\n### L1 human\n\nThe moments of a mass distribution on $[0, 1]$ are its total mass, its mean position, its mean squared position, and so on.\nThe problem asks which lists of numbers can occur as such moments.\nNot every list works: for instance, the moments can never increase, since $x^{n+1} \\le x^n$ on $[0, 1]$.\nHausdorff found an exact test, a sign condition on all repeated differences of the list, and showed that the list then determines the distribution.\n",
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      "first_stated": "1921",
      "posed_by": "Felix Hausdorff"
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