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  "body": "\n## Definition\n\nLet $X$ be a [[topological space|0CQHFPGJ45]].\nA subset $C \\subseteq X$ is irreducible when $C \\ne \\varnothing$ and the following holds.\nIf $C = A \\cup B$ with $A$ and $B$ [[closed|0ZCK8DQYN1]] in the subspace $C$, then $A = C$ or $B = C$.\nA point $x$ is a generic point of a closed set $C$ when the [[closure|0QEAJB91GZ]] $\\overline{\\set{x}}$ equals $C$.\n$X$ is *sober* when every irreducible closed subset of $X$ has exactly one generic point.\n\n## Remarks\n\nFor each point $x$, the closure $\\overline{\\set{x}}$ is irreducible and closed, with generic point $x$.\nSo the uniqueness part says that $\\overline{\\set{x}} = \\overline{\\set{y}}$ implies $x = y$, and a sober space is [[T0|07SG12TQH3]].\nEvery [[Hausdorff space|0S1FJ8VEX9]] is sober, because its irreducible subsets are single points.\n\nExample: for a commutative ring $R$, the spectrum $\\operatorname{Spec} R$ with the Zariski topology is sober.\nAn irreducible closed set has the form $V(\\mathfrak p) = \\set{\\mathfrak q : \\mathfrak q \\supseteq \\mathfrak p}$ for a unique [[prime ideal|00MHHZ9SNE]] $\\mathfrak p$, and $\\mathfrak p$ is its generic point.\n\nNon-example: an infinite set $X$ with the [[cofinite topology|0B906ZBTMZ]] is not sober.\n$X$ is irreducible, since two proper closed sets are finite and their union is not $X$.\nBut each point is closed, so $\\overline{\\set{x}} = \\set{x} \\ne X$, and $X$ has no generic point.\n",
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