{
  "aliases": null,
  "backlinks": null,
  "body": "\n## Statement\n\nLet $a_1, a_2, \\dots$ and $b_1, b_2, \\dots$ be complex numbers such that $\\abs{b_n} \\ge \\abs{a_n} + 1$ for every $n \\ge 1$.\nThen the [[continued fraction|0BK6JBK58W]]\n$$f = \\cfrac{a_1}{b_1 + \\cfrac{a_2}{b_2 + \\cfrac{a_3}{b_3 + \\cdots}}}$$\nconverges, and its value satisfies $\\abs{f} \\le 1$.\n\n## Remarks\n\nProof idea: with the [[fundamental recurrence formulas|6WYYMPH21Q]] ($b_0 = 0$), the denominators satisfy $\\abs{B_n} \\ge (\\abs{a_n} + 1)\\abs{B_{n-1}} - \\abs{a_n}\\abs{B_{n-2}}$.\nBy induction $\\abs{B_n} - \\abs{B_{n-1}} \\ge \\abs{a_1 \\cdots a_n}$, so $1 = \\abs{B_0} \\le \\abs{B_1} \\le \\cdots$ and no $B_n$ vanishes.\nThen $\\abs{f_n - f_{n-1}} = \\frac{\\abs{a_1 \\cdots a_n}}{\\abs{B_n}\\abs{B_{n-1}}} \\le \\frac{1}{\\abs{B_{n-1}}} - \\frac{1}{\\abs{B_n}}$, and this telescopes: the series $\\sum (f_n - f_{n-1})$ converges absolutely with total at most $1$, where $f_0 = 0$.\nExample: $a_n = 1$ and $b_n = 2$ satisfy the condition, and the value is $\\sqrt{2} - 1$.\nThe condition cannot simply be dropped: for $a_n = -1$ and $b_n = 1$ one has $\\abs{b_n} \u003c \\abs{a_n} + 1$, and the convergents repeat the cycle $-1, \\infty, 0$, so the continued fraction diverges.\n\n## Explanations\n\n### L1 human\n\nA continued fraction converges when each partial denominator is larger than the partial numerator by at least one in absolute value.\nThe value then lies in the closed unit disc.\n\n### L2 human\n\nThis is a basic sufficient condition for convergence, in the same spirit as the comparison test for series.\nEach map $w \\mapsto \\frac{a_n}{b_n + w}$ sends the closed unit disc into itself under the hypothesis, which explains the bound $\\abs{f} \\le 1$.\nThe [[Van Vleck theorem|KCCFZTP3MM]] is another classical criterion, for partial denominators in a sector.\n",
  "commit": "547b6eddb8f2feb8d579f2d633d22a27b7e132fc",
  "front": {
    "about": [
      "04P2RJ4WPS"
    ],
    "kind": "statement",
    "msc": [
      "40A15",
      "30B70"
    ],
    "name": "Śleszyński–Pringsheim theorem",
    "role": "theorem",
    "same_as": {
      "wikidata": "Q8081891",
      "wikipedia": "Śleszyński–Pringsheim theorem"
    },
    "sources": [
      {
        "url": "https://en.wikipedia.org/wiki/Śleszyński–Pringsheim_theorem"
      }
    ],
    "tag": "NEC48RHNN0",
    "uses": [
      "0BK6JBK58W",
      "0SRWNR42BQ",
      "6WYYMPH21Q"
    ]
  },
  "kind": "statement",
  "link": "https://math2.tamnd.com/node/NEC48RHNN0/",
  "links": [
    {
      "field": "about",
      "target": "04P2RJ4WPS"
    },
    {
      "field": "uses",
      "target": "0BK6JBK58W"
    },
    {
      "field": "uses",
      "target": "0SRWNR42BQ"
    },
    {
      "field": "uses",
      "target": "6WYYMPH21Q"
    }
  ],
  "markdown": "https://math2.tamnd.com/node/NEC48RHNN0.md",
  "msc": [
    "40A15",
    "30B70"
  ],
  "name": "Śleszyński–Pringsheim theorem",
  "prov": null,
  "role": "theorem",
  "source": "https://github.com/tamnd/math2/blob/main/nodes/NEC/NEC48RHNN0.md",
  "status": null,
  "tag": "NEC48RHNN0",
  "uri": "m2://NEC48RHNN0",
  "url": "https://math2.tamnd.com/wiki/sleszynski-pringsheim-theorem/",
  "writing": {
    "tag": "NEC48RHNN0",
    "kind": "statement",
    "level": "W0",
    "next": [
      {
        "what": "an inventory row",
        "note": "the row of the inventory that the node accounts for",
        "have": 0,
        "want": 1
      },
      {
        "what": "a source with a locator",
        "have": 0,
        "want": 1
      }
    ]
  }
}
