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  "body": "\n## Definition\n\nLet $R$ be a [[commutative ring|0310REJJY8]] and let $f \\in R$.\nThe *basic open set* (or *principal open set*) of $f$ is the subset\n$$D(f) = \\set{\\mathfrak p \\in \\operatorname{Spec} R : f \\notin \\mathfrak p}$$\nof the [[spectrum|FB45BHHA2J]] of $R$.\nIt is the complement of the closed set $V(\\set{f})$ of the [[Zariski topology|8SQK7RTB63]], hence open.\n\n## Remarks\n\nThe basic open sets have these properties, for $f, g \\in R$:\n\n1. $D(f) \\cap D(g) = D(fg)$, since a [[prime ideal|00MHHZ9SNE]] contains $fg$ exactly when it contains $f$ or $g$;\n2. each open set $X \\setminus V(E)$ equals $\\bigcup_{f \\in E} D(f)$, so the sets $D(f)$ form a [[basis|0NA0732YAG]] of the topology;\n3. $D(f) = \\emptyset$ exactly when $f$ is [[nilpotent|0ZB2JG1M9C]], and $D(f) = \\operatorname{Spec} R$ exactly when $f$ is a [[unit|0XVEZDE9J8]];\n4. the map $\\operatorname{Spec} R_f \\to \\operatorname{Spec} R$ induced by $R \\to R_f$ is a homeomorphism onto $D(f)$; see [[prime ideals of a localization|W8QNZZ4QJS]].\n\nExample: in $\\operatorname{Spec} \\Z$, the set $D(6)$ consists of $(0)$ and all $p\\Z$ with $p \\ne 2, 3$.\n\nNon-example: not every open set is basic.\nLet $k$ be a field and $R = k[x, y]$.\nThe set $U = \\operatorname{Spec} R \\setminus \\set{(x, y)}$ is open, because $\\set{(x,y)} = V(\\set{x, y})$.\nIf $U = D(f)$, then $f \\ne 0$ and $f$ is not a unit, since $U$ is neither empty nor everything.\nThen an irreducible factor $g$ of $f$ generates a prime ideal $(g)$ that contains $f$, and $(g) \\ne (x, y)$ because $(x,y)$ is not principal.\nSo $(g) \\notin D(f)$ but $(g) \\in U$, a contradiction.\n",
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