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  "body": "\n## Statement\n\nLet $(X, \\Sigma, \\mu)$ be a measure space, let $1 \\le p \u003c \\infty$, and let $q \\in (1, \\infty]$ be the conjugate exponent, with $1/p + 1/q = 1$.\nIf $p = 1$, assume moreover that $\\mu$ is [[σ-finite|WEBBT18D4X]].\nFor $g \\in L^q(\\mu)$, let $\\Lambda_g$ be the functional on [[$L^p(\\mu)$|SASP14MA1Z]] given by\n$$\\Lambda_g(f) = \\int_X f g \\, d\\mu.$$\nThen $g \\mapsto \\Lambda_g$ is an [[isometric isomorphism|0ZXSF2YQV2]] of $L^q(\\mu)$ onto the [[dual space|07JBSZE0V4]] $L^p(\\mu)^*$.\n\n## Remarks\n\nHölder's inequality gives $\\abs{\\Lambda_g(f)} \\le \\norm{f}_p \\norm{g}_q$, so $\\norm{\\Lambda_g} \\le \\norm{g}_q$.\nFor $1 \u003c p \u003c \\infty$, the choice $f = \\abs{g}^{q-1} \\overline{\\sgn g}$ gives equality, so the map is an isometry.\nSurjectivity is the main point.\nLet $\\mu$ be $\\sigma$-finite and let $\\Lambda$ be a bounded functional.\nThen $E \\mapsto \\Lambda(\\mathbf{1}_E)$, on sets of finite measure, is a set function absolutely continuous with respect to $\\mu$.\nThe [[Radon–Nikodym theorem|1ZSZS5G1Q4]] gives $g$.\nFor $1 \u003c p \u003c \\infty$ and a general measure space, one reduces to the $\\sigma$-finite case, or uses the uniform convexity of $L^p$.\n\nExample: for counting measure on $\\N$, the theorem says that $(\\ell^p)^* = \\ell^q$ for $1 \\le p \u003c \\infty$.\n\nThe $\\sigma$-finiteness for $p = 1$ cannot be dropped.\nLet $X = \\set{x}$ with $\\mu(\\set{x}) = \\infty$.\nThen $L^1(\\mu) = \\set{0}$, whose dual is $\\set{0}$, but $L^\\infty(\\mu)$ is the one-dimensional space of constants.\n\nThe case $p = \\infty$ is excluded.\nThe map $g \\mapsto \\Lambda_g$ from $L^1$ into $(L^\\infty)^*$ is an isometry, but in general it is not onto.\nFor example, take the functional on convergent sequences that gives the limit.\nBy the Hahn–Banach theorem it extends to a bounded functional on $\\ell^\\infty$, and this extension is not given by any element of $\\ell^1$.\n\n## Explanations\n\n### L1 human\n\nEvery continuous linear way of turning a function in $L^p$ into a number is integration against a fixed function $g$.\nThe function $g$ lives in the partner space $L^q$, where $1/p + 1/q = 1$.\nSo $L^2$ is its own partner, $L^1$ is paired with $L^\\infty$, and $L^{3/2}$ is paired with $L^3$.\n\n### L2 human\n\nThe theorem identifies $(L^p)^* = L^q$ for $1 \\le p \u003c \\infty$ under the stated hypotheses.\nFor $1 \u003c p \u003c \\infty$ it follows that $L^p$ is reflexive, since $(L^p)^{**} = (L^q)^* = L^p$.\nWeak convergence in $L^p$ then means convergence of $\\int f_n g \\, d\\mu$ for each $g \\in L^q$, and bounded sequences have weakly convergent subsequences.\nNeither $L^1$ nor $L^\\infty$ is reflexive in general, which is the source of many technical difficulties.\n",
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