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  "body": "\n## Statement\n\nLet $X$ be a [[separable Banach space|AH45GS6RCR]] over $\\R$.\nLet $C([0,1])$ be the Banach space of continuous real functions on $[0,1]$ with the [[supremum norm|0PARCKE8WP]].\nThen there is a [[linear isometry|07SJXTWVQW]] $T \\colon X \\to C([0,1])$.\nIn particular, $X$ is isometrically isomorphic to the closed subspace $T(X)$ of $C([0,1])$.\n\n## Remarks\n\nThe idea of the proof: let $B$ be the closed unit ball of the dual space $X^*$ with the weak-* topology.\nSince $X$ is separable, $B$ is a compact metrizable space, so it is a continuous image of the Cantor set $\\Delta$ under some map $\\varphi$.\nThe map $x \\mapsto (t \\mapsto \\varphi(t)(x))$ is a linear isometry of $X$ into $C(\\Delta)$, by the Hahn–Banach theorem.\nEach function in $C(\\Delta)$ extends to $[0,1]$ by linear interpolation on the open intervals removed from $[0,1]$, and this extension is a linear isometry from $C(\\Delta)$ into $C([0,1])$.\n\nFor example, the Hilbert space $\\ell^2$ and every space $L^p([0,1])$ with $1 \\le p \u003c \\infty$ are isometric to subspaces of $C([0,1])$.\nSeparability is necessary: $C([0,1])$ is separable, so each of its subspaces is separable, and the non-separable space $\\ell^\\infty$ does not embed in it.\n\n## Explanations\n\n### L1 human\n\nThe space of continuous functions on an interval is big enough to hold a copy of every separable Banach space.\nThe copy keeps all distances exactly.\nSo questions about separable Banach spaces can be asked inside one single space.\n\n### L2 human\n\nThe theorem says that $C([0,1])$ is universal for the class of separable Banach spaces.\nIt is the linear analogue of the fact that every compact metric space is a continuous image of the Cantor set, and the proof uses exactly that fact.\nThe weak-* compactness of the dual ball comes from the Banach–Alaoglu theorem.\nUniversality makes $C([0,1])$ itself very complicated: every property that fails in some separable space fails in some subspace of $C([0,1])$.\n",
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