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  "body": "\n## Statement\n\nLet $k$ be a [[field|04C5ZBG1WT]] and let $K$ be a field extension of $k$ that is [[finitely generated|AC5TFFQT9M]] as a $k$-algebra.\nThen $K$ is a [[finite extension|0C1Y04SZ1W]] of $k$.\n\n## Remarks\n\nBy [[Noether normalization|7Z28JY8QW4]], $K$ is finite over a polynomial ring $k[y_1, \\ldots, y_d]$.\nBy [[integral extensions of fields|5GCANV7337]], $k[y_1, \\ldots, y_d]$ is then a field, which forces $d = 0$, since $y_1$ has no inverse in a polynomial ring when $d \\ge 1$.\nSo $K$ is finite over $k$.\nAnother proof uses the [[Artin–Tate lemma|4MBR0W0S6N]].\n\nExample: $\\Q(\\sqrt{2}) = \\Q[\\sqrt{2}]$ is a field generated by one element as a $\\Q$-algebra, and it is finite over $\\Q$ of degree $2$.\n\nThe lemma is about generation as an algebra.\nThe field $k(t)$ of rational functions is generated by $t$ as a field, but it is not a finitely generated $k$-algebra, and it is not finite over $k$.\n\n## Explanations\n\n### L1 human\n\nA field that can be built from a smaller field with finitely many elements, using only addition and multiplication, is a finite extension of it.\nInverses come for free in such a field, so no transcendental element can occur.\n\n### L2 human\n\nZariski's lemma is the algebraic core of the [[weak Nullstellensatz|ZWS0YWGF17]].\nIf $\\mathfrak{m}$ is a maximal ideal of $k[x_1, \\ldots, x_n]$, then $k[x_1, \\ldots, x_n]/\\mathfrak{m}$ is a field finitely generated as a $k$-algebra, so it is finite over $k$.\nWhen $k$ is algebraically closed, this residue field is $k$ itself, and $\\mathfrak{m}$ is the ideal of a point.\n",
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