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  "body": "\n## Definition\n\nLet $H$ be a complex [[Hilbert space|HM2HHE3J51]], and let $A$ be a [[symmetric operator|H971WGMV6C]] on $H$ with dense domain $D(A)$.\nThen $A$ is [[closable|3TWMBFQJJ8]], with [[closure|TRC892PJNN]] $\\overline{A}$.\nThe operator $A$ is *essentially self-adjoint* if $\\overline{A}$ is self-adjoint, that is, $\\overline{A} = (\\overline{A})^*$, where ${}^*$ denotes the [[adjoint|86B7HF79PQ]].\n\n## Remarks\n\nThe following conditions are equivalent for a symmetric operator $A$:\n\n1. $A$ is essentially self-adjoint;\n2. $A$ has exactly one self-adjoint extension;\n3. $A^*$ is self-adjoint, and then $A^* = \\overline{A}$;\n4. the [[kernels|0S23E6YE83]] $\\ker(A^* - iI)$ and $\\ker(A^* + iI)$ are both $\\set{0}$.\n\nExample: on $L^2(\\R)$, let $A = -i \\, d/dx$ on the smooth functions with compact support.\nThen $A^*$ is $-i \\, d/dx$ on the Sobolev space $H^1(\\R)$.\nThe equation $A^* u = \\pm i u$ means $u' = \\mp u$, with solutions $c e^{\\mp x}$, which are not in $L^2(\\R)$ unless $c = 0$; so condition 4 holds.\nNon-example: on $L^2([0,1])$, let $B = -i \\, d/dx$ on the smooth functions with compact support in $(0,1)$.\nNow $e^{-x}$ and $e^{x}$ lie in $L^2([0,1])$ and solve $B^* u = i u$ and $B^* u = -i u$, so condition 4 fails, and $B$ has many self-adjoint extensions, one for each boundary condition $u(1) = e^{i \\theta} u(0)$.\nA self-adjoint operator is essentially self-adjoint; a core of a self-adjoint operator $T$ is a domain on which the restriction of $T$ is essentially self-adjoint.\n",
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