---
tag: EWHNSZ4X5F
kind: problem
name: Problem in words
sources:
  - wikipedia: en:9710@r1357801777
    locator: Elementary algebra, section Solving algebraic equations > Linear equations with two variables
    note: adopted
    mention: wikipedia://en/9710#TFL4
    sections: [Problem]
inventory: [S5GATSJNQ6]
---

## Problem

In 10 years, the father will be twice as old as his son.

**Equivalent equation**

$$\begin{aligned} y + 10 &= 2 \times (x + 10)\\ y &= 2 \times (x + 10) - 10 && \text{Subtract 10 from both sides}\\ y &= 2x + 20 - 10 && \text{Multiple out brackets}\\ y &= 2x + 10 && \text{Simplify} \end{aligned}$$

Now there are two related linear equations, each with two unknowns, which enables the production of a linear equation with just one variable, by subtracting one from the other (called the elimination method):

$$\begin{cases} y = x + 22 & \text{First equation}\\ y = 2x + 10 & \text{Second equation} \end{cases}$$

$$\begin{aligned} &&&\text{Subtract the first equation from}\\ (y - y) &= (2x - x) +10 - 22 && \text{the second in order to remove } y\\ 0 &= x - 12 && \text{Simplify}\\ 12 &= x && \text{Add 12 to both sides}\\ x &= 12 && \text{Rearrange} \end{aligned}$$

In other words, the son is aged 12, and since the father 22 years older, he must be 34. In 10 years, the son will be 22, and the father will be twice his age, 44. This problem is illustrated on the associated plot of the equations.

For other ways to solve this kind of equations, see below, **System of linear equations**.