Math 2.0

Mathematical logic and foundations Proposition

Formula for the inverse

Statement

Many functions given by algebraic formulas possess a formula for their inverse. This is because the inverse f−1f^{-1} of an invertible function f ⁣:ℝ→ℝf\colon\mathbb{R}\to\mathbb{R} has an explicit description as

f−1(y)=(the unique element x∈ℝ such that f(x)=y).f^{-1}(y)=(\text{the unique element }x\in \mathbb{R}\text{ such that }f(x)=y).

This allows one to easily determine inverses of many functions that are given by algebraic formulas. For example, if ff is the function

f(x)=(2x+8)3f(x) = (2x + 8)^3

then to determine f−1(y)f^{-1}(y) for a real number yy, one must find the unique real number xx such that (2x+8)3=y(2x + 8)^{3} = y. This equation can be solved:

y=(2x+8)3y3=2x+8y3−8=2xy3−82=x.\begin{aligned} y & = (2x+8)^3 \\ \sqrt[3]{y} & = 2x + 8 \\ \sqrt[3]{y} - 8 & = 2x \\ \dfrac{\sqrt[3]{y} - 8}{2} & = x . \end{aligned}

Thus the inverse function f −1f^{\,-1} is given by the formula

f−1(y)=y3−82.f^{-1}(y) = \frac{\sqrt[3]{y} - 8} 2.

Sometimes, the inverse of a function cannot be expressed by a closed-form formula. For example, if ff is the function

f(x)=x−sin⁡x,f(x) = x - \sin x ,

then ff is a bijection, and therefore possesses an inverse function f −1f^{\,-1}. The formula for this inverse has an expression as an infinite sum:

f−1(y)=∑n=1∞yn/3n!lim⁡θ→0(d n−1dθ n−1(θθ−sin⁡(θ)3)n).f^{-1}(y) = \sum_{n=1}^\infty \frac{y^{n/3}}{n!} \lim_{ \theta \to 0} \left( \frac{\mathrm{d}^{\,n-1}}{\mathrm{d} \theta^{\,n-1}} \left( \frac \theta { \sqrt[3]{ \theta - \sin( \theta )} } \right)^n \right).

Further reading

  1. Wikipedia, page 14907, revision 1368588964, Inverse function, section Examples > Formula for the inverse. adopted
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Changed4 November 2026

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