Math 2.0

Statistical mechanics, structure of matter Lattice spin systems Example

Ising model

Example

Let G=(V,E)G = (V, E) be a finite graph, and let J>0J > 0, h∈ℝh \in \R and β≥0\beta \ge 0 be real numbers. A spin configuration is a map σ ⁣:V→{−1,+1}\sigma \colon V \to \set{-1, +1}. Its energy is H(σ)=−J∑{u,v}∈Eσ(u)σ(v)−h∑v∈Vσ(v).H(\sigma) = -J \sum_{\set{u, v} \in E} \sigma(u) \sigma(v) - h \sum_{v \in V} \sigma(v). The Ising model on GG at inverse temperature β\beta is the probability measure on {−1,+1}V\set{-1, +1}^V given by μβ(σ)=e−βH(σ)Zβ,Zβ=∑τ∈{−1,+1}Ve−βH(τ).\mu_\beta(\sigma) = \frac{e^{-\beta H(\sigma)}}{Z_\beta}, \qquad Z_\beta = \sum_{\tau \in \set{-1, +1}^V} e^{-\beta H(\tau)}. Check: each weight e−βH(σ)e^{-\beta H(\sigma)} is positive and there are finitely many configurations. So Zβ>0Z_\beta > 0, and the values of μβ\mu_\beta are positive and sum to 11.

Remarks

With J>0J > 0, neighbouring spins prefer to agree, and the measure favours aligned configurations more strongly as β\beta grows. At β=0\beta = 0 the spins are independent and uniform. On the infinite lattice ℤd\Z^d, limits of these measures as GG grows are Gibbs measures. For h=0h = 0 and d≥2d \ge 2 there is a phase transition: there is more than one Gibbs measure for large β\beta and only one for small β\beta. For d=1d = 1 there is no phase transition. For d=2d = 2 and h=0h = 0, Onsager's solution gives the critical value βc\beta_c by sinh⁡(2βcJ)=1\sinh(2 \beta_c J) = 1, that is βc=ln⁡(1+2)2J\beta_c = \frac{\ln(1 + \sqrt 2)}{2J}. Its Glauber dynamics, in which single spins flip at random, is an interacting particle system with μβ\mu_\beta as invariant measure.

Further reading

  1. Web https://en.wikipedia.org/wiki/Ising_model
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Changed2 November 2026

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