Math 2.0

Field theory and polynomials Real fields and ordered fields Object

Levi-Civita field

Description

A function a ⁣:ℚ→ℝa \colon \Q \to \R has left-finite support if for every q∈ℚq \in \Q there are only finitely many r<qr < q with a(r)≠0a(r) \ne 0. The Levi-Civita field ℛ\mathcal{R} is the set of such functions, written as formal sums a=∑q∈ℚa(q) εqa = \sum_{q \in \Q} a(q)\, \varepsilon^q. Addition is termwise, and the product is (ab)(q)=∑r+s=qa(r)b(s)(ab)(q) = \sum_{r + s = q} a(r) b(s), a finite sum because both supports are left-finite. For a≠0a \ne 0, let q0q_0 be the least qq with a(q)≠0a(q) \ne 0; then a>0a > 0 means a(q0)>0a(q_0) > 0. With these operations and this order, ℛ\mathcal{R} is an ordered field that contains ℝ\R as the constant series.

Remarks

Check that ε=1⋅ε1\varepsilon = 1 \cdot \varepsilon^1 is a positive infinitesimal: ε>0\varepsilon > 0 since its leading coefficient is 11, and for each integer n≥1n \ge 1 the element 1/n−ε1/n - \varepsilon has leading term 1nε0\frac{1}{n} \varepsilon^0, so it is positive. Hence ℛ\mathcal{R} is not Archimedean, and ε−1\varepsilon^{-1} is larger than every real number. Since exponents are rational, ε\varepsilon has roots of every order, for example (ε1/2)2=ε(\varepsilon^{1/2})^2 = \varepsilon. The field ℛ\mathcal{R} is real closed, and it is Cauchy complete for the topology of its order. Adjoining a square root of −1-1 gives an algebraically closed field.

Further reading

  1. Web https://en.wikipedia.org/wiki/Levi-Civita_field
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MSC12J15, 12J25
Instance ofOrdered field
Same as
Changed2 November 2026

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