Alhazen's problem
Problem
Let be a circle with centre in the plane. Let and be two points of the plane that do not lie on . Find the points on at which a ray from is reflected to by the law of reflection. These are the points such that the line bisects the angle .
Remarks
The circle is the cross-section of a spherical mirror by the plane through , and the centre of the sphere. So the problem asks where to look in a spherical mirror to see a given point. Ibn al-Haytham (Alhazen) solved it geometrically with the help of conic sections. In coordinates, the condition on leads to a polynomial equation of degree . Peter M. Neumann proved in 1997 that the points cannot in general be constructed with ruler and compass, so the problem is not a problem of constructible numbers.
Reading path
To understand this page from the ground up, read these 10 pages in order. The foundations come first.
Show the path as a graph
- no evidence level
- Calculus of variations concept
- Circle concept
- Constructible number concept
- Euler–Lagrange equation concept
- Geodesic concept
- Normal vector concept
- Reflection concept
- Fermat's principle statement
- Law of reflection statement
- Alhazen's problem problem
Further reading
About this page
| Tag | AZ2NV4EBAY |
|---|---|
| URI | m2://AZ2NV4EBAY |
| Kind | problem |
| Writing | W0 stub |
| MSC | 51M15, 78A05, 51M04 |
| Status | This copy of the site has no build data. Run m2 status AZ2NV4EBAY. |
| About | Law of reflection |
| Uses | Law of reflection, Circle, Constructible number |
| Same as | |
| Changed | 3 November 2026 |
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