Math 2.0

Theorem

André's theorem

Statement

The determination of the number An of alternating permutations of the set {1, ..., n} is called André's problem. The numbers An are variously known as Euler numbers, zigzag numbers, up/down numbers, or by some combinations of these names. The name Euler numbers in particular is sometimes used for a closely related sequence. The first few values of An are 1, 1, 1, 2, 5, 16, 61, 272, 1385, 7936, 50521, ... .

These numbers satisfy a simple recurrence, similar to that of the Catalan numbers: by splitting the set of alternating permutations (both down-up and up-down) of the set { 1, 2, 3, ..., n, n + 1 } according to the position k of the largest entry n+1n + 1, one can show that

2An+1=∑k=0n(nk)AkAn−k2A_{n+1} = \sum_{k=0}^n \binom{n}{k} A_k A_{n-k}

for all n≥1n \ge 1. (André 1881) used this recurrence to give a differential equation satisfied by the exponential generating function

A(x)=∑n=0∞Anxnn!A(x) = \sum_{n=0}^\infty A_n \frac{x^n}{n!}

for the sequence AnA_{n}. In fact, the recurrence gives:

2∑n≥1An+1xn+1(n+1)!=∑n≥1∑k=0nAkk!An−k(n−k)!xn+1n+1=∫(∑k≥0Akxkk!)(∑j≥0Ajxjj!) dx−x2\sum_{n\geq 1} A_{n+1} \frac{x^{n+1}}{(n+1)!} = \sum_{n\geq 1} \sum_{k=0}^n \frac{A_k}{k!} \frac{A_{n-k}}{(n-k)!} \frac{x^{n+1}}{n+1} = \int \left(\sum_{k\geq 0}A_k \frac{x^k}{k!}\right) \left(\sum_{j\geq 0}A_j \frac{x^j}{j!}\right) \, dx - x

where we substitute j=n−kj = n-k and xn+1n+1=∫xk+j dx\frac{x^{n+1}}{n+1}=\int x^{k+j}\,dx. This gives the integral equation

2(A(x)−1−x)=∫A(x)2 dx−x,2(A(x) - 1 - x) = \int A(x)^2\,dx - x,

which after differentiation becomes 2dAdx−2=A2−12\frac{dA}{dx} - 2 = A^2-1. This differential equation can be solved by separation of variables (using the initial condition A(0)=A0/0!=1A(0)=A_0/0!=1), and simplified using a tangent half-angle formula, giving the final result

A(x)=tan⁡(π4+x2)=sec⁡x+tan⁡x,A(x) = \tan \left(\frac\pi4 + \frac x2\right) = \sec x + \tan x,

the sum of the secant and tangent functions. This result is known as André's theorem. A geometric interpretation of this result can be given using a generalization of a theorem by Johann Bernoulli.

It follows from André's theorem that the radius of convergence of the series A(x)A(x) is π\pi/2. This allows one to compute the asymptotic expansion

An∼2(2π)n+1n! .A_n \sim 2 \left(\frac{2}{\pi}\right)^{n + 1} n!\,.

Further reading

  1. Wikipedia, page 4813617, revision 1362588099, Alternating permutation, section André's theorem. adopted
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