Group theory and generalizations Infinite groups and combinatorial group theory Conjecture
Andrews–Curtis conjecture
Builds on Presentation of a groupFree groupConjugate elements
Statement
A presentation is balanced if it has as many relators as generators. The Andrews–Curtis moves on such a presentation, with elements of the free group on , are:
- replace some by ;
- replace some by for some ;
- replace some by for some .
The conjecture: every balanced presentation of the trivial group can be turned into the trivial presentation by a finite sequence of Andrews–Curtis moves.
Remarks
Each move keeps the normal closure of the relators, so it keeps the group. A presentation of the trivial group with generators has at least relators, since the abelianization must become trivial; so the balanced ones are the extreme case. A weaker stable form of the conjecture also allows adding a generator with relator , and removing such a pair. Andrews and Curtis stated the conjecture in 1965, in connection with the topology of -dimensional complexes and -dimensional manifolds. It is open; many experts expect it to be false, and several families of balanced presentations of the trivial group are studied as potential counterexamples.
Reading path
To understand this page from the ground up, read these 4 pages in order. The foundations come first.
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- no evidence level
- Conjugate elements concept
- Free group concept
- Presentation of a group concept
- Andrews–Curtis conjecture conjecture
Further reading
About this page
| Tag | N298DRYE0W |
|---|---|
| URI | m2://N298DRYE0W |
| Kind | conjecture |
| Writing | W0 stub |
| MSC | 20F05, 57M20 |
| Status | This copy of the site has no build data. Run m2 status N298DRYE0W. |
| About | Presentation of a group |
| Uses | Presentation of a group, Free group, Conjugate elements |
| Same as | |
| Changed | 2 November 2026 |
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