Math 2.0

Measure and integration Definition

Choquet capacity

Builds on Compact spaceHausdorff space

Definition

Let XX be a Hausdorff space, and let 𝒫(X)\mathcal{P}(X) be the set of all subsets of XX. A Choquet capacity on XX is a map I ⁣:𝒫(X)→[0,∞]I \colon \mathcal{P}(X) \to [0, \infty] with the following properties.

  1. If A⊆B⊆XA \subseteq B \subseteq X, then I(A)≤I(B)I(A) \le I(B).
  2. If A1⊆A2⊆⋯A_1 \subseteq A_2 \subseteq \cdots are subsets of XX with union AA, then I(Ak)→I(A)I(A_k) \to I(A).
  3. If K1⊇K2⊇⋯K_1 \supseteq K_2 \supseteq \cdots are compact subsets of XX with intersection KK, then I(Kk)→I(K)I(K_k) \to I(K).

A set A⊆XA \subseteq X is capacitable for II if I(A)=sup⁡{I(K):K⊆A, K compact}I(A) = \sup \set{I(K) : K \subseteq A, \ K \text{ compact}}.

Remarks

Example: let μ\mu be a finite Borel measure on ℝn\R^n and μ∗\mu^* its outer measure, μ∗(A)=inf⁡{μ(B):B⊇A Borel}\mu^*(A) = \inf \set{\mu(B) : B \supseteq A \text{ Borel}}. Clause 1 is clear. Clause 2 holds because each AkA_k has a Borel hull BkB_k with μ(Bk)=μ∗(Ak)\mu(B_k) = \mu^*(A_k), and the sets ⋂j≥kBj\bigcap_{j \ge k} B_j increase to a Borel hull of AA. Clause 3 is continuity from above of the finite measure μ\mu. Non-example: on ℝ\R let I(A)=1I(A) = 1 if AA is infinite and I(A)=0I(A) = 0 otherwise. The finite sets {1,…,k}\set{1, \dots, k} increase to the infinite set ℕ∖{0}\N \setminus \set{0}, but I=0I = 0 along the sequence, so clause 2 fails. Choquet's capacitability theorem: if XX is a Polish space, every analytic subset of XX is capacitable for every Choquet capacity. Some authors allow values in [−∞,∞][-\infty, \infty] or define capacities relative to a paving other than the compact sets.

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Further reading

  1. Web https://en.wikipedia.org/wiki/Capacity_of_a_set
About this page
TagYG74XH44H6
URIm2://YG74XH44H6
Kinddefinition
WritingW0 stub
MSC28A12, 31C15
DefinesChoquet capacity
UsesCompact space, Hausdorff space
Changed2 November 2026

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