Math 2.0

Associative rings and algebras Definition

Coalgebra

Builds on FieldVector spaceTensor product of vector spacesLinear map

Definition

Let KK be a field. A coalgebra over KK is a vector space CC over KK with linear maps Δ ⁣:C→C⊗C\Delta \colon C \to C \otimes C, the comultiplication, and ε ⁣:C→K\varepsilon \colon C \to K, the counit, such that:

  1. (Δ⊗id⁡C)∘Δ=(id⁡C⊗Δ)∘Δ(\Delta \otimes \id_C) \circ \Delta = (\id_C \otimes \Delta) \circ \Delta as maps C→C⊗C⊗CC \to C \otimes C \otimes C (coassociativity).
  2. (ε⊗id⁡C)∘Δ=id⁡C=(id⁡C⊗ε)∘Δ(\varepsilon \otimes \id_C) \circ \Delta = \id_C = (\id_C \otimes \varepsilon) \circ \Delta, where K⊗CK \otimes C and C⊗KC \otimes K are identified with CC (counit law).

Here ⊗\otimes is the tensor product over KK.

Remarks

Example: for a set SS, let C=K[S]C = K[S] be the vector space with basis SS, and put Δ(s)=s⊗s\Delta(s) = s \otimes s and ε(s)=1\varepsilon(s) = 1 for s∈Ss \in S. Both sides of clause 1 send ss to s⊗s⊗ss \otimes s \otimes s, and both maps in clause 2 send ss to 1⋅s=s1 \cdot s = s. Non-example: the same Δ\Delta with ε(s)=0\varepsilon(s) = 0 for all ss fails clause 2, since (ε⊗id⁡)Δ(s)=0≠s(\varepsilon \otimes \id)\Delta(s) = 0 \ne s. Another example is K[x]K[x] with Δ(xn)=∑k=0n(nk)xk⊗xn−k\Delta(x^n) = \sum_{k=0}^{n} \binom{n}{k} x^k \otimes x^{n-k} and ε(xn)=1\varepsilon(x^n) = 1 if n=0n = 0 and 00 otherwise. The definition works in the same way over a commutative ring in place of KK. Over a field, every element of a coalgebra lies in a finite-dimensional subcoalgebra.

Reading path

To understand this page from the ground up, read these 5 pages in order. The foundations come first.

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  1. Field concept
  2. Linear map concept
  3. Tensor product of vector spaces concept
  4. Vector space concept
  5. Coalgebra definition

Further reading

  1. Web https://en.wikipedia.org/wiki/Coalgebra
About this page
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Kinddefinition
WritingW0 stub
MSC16T15
DefinesCoalgebra
UsesField, Vector space, Tensor product of vector spaces, Linear map
Changed2 November 2026

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