Math 2.0

Associative rings and algebras Definition

Comodule

Builds on CoalgebraVector spaceTensor product of vector spacesLinear map

Definition

Let KK be a field and let (C,Δ,ε)(C, \Delta, \varepsilon) be a coalgebra over KK. A right CC-comodule is a vector space MM over KK with a linear map ρ ⁣:M→M⊗C\rho \colon M \to M \otimes C, the coaction, such that:

  1. (id⁡M⊗Δ)∘ρ=(ρ⊗id⁡C)∘ρ(\id_M \otimes \Delta) \circ \rho = (\rho \otimes \id_C) \circ \rho as maps M→M⊗C⊗CM \to M \otimes C \otimes C.
  2. (id⁡M⊗ε)∘ρ=id⁡M(\id_M \otimes \varepsilon) \circ \rho = \id_M, where M⊗KM \otimes K is identified with MM.

A left CC-comodule is defined in the same way with a map M→C⊗MM \to C \otimes M.

Remarks

Example: CC is a right comodule over itself with ρ=Δ\rho = \Delta; clauses 1 and 2 are coassociativity and the counit law. Example: let C=K[S]C = K[S] with Δ(s)=s⊗s\Delta(s) = s \otimes s and ε(s)=1\varepsilon(s) = 1, and let M=⨁s∈SMsM = \bigoplus_{s \in S} M_s be a vector space graded by SS. Then ρ(m)=m⊗s\rho(m) = m \otimes s for m∈Msm \in M_s is a coaction: both sides of clause 1 give m⊗s⊗sm \otimes s \otimes s, and clause 2 gives ε(s)m=m\varepsilon(s) m = m. Every right K[S]K[S]-comodule arises in this way. Non-example: for M≠0M \ne 0, the zero map ρ=0\rho = 0 satisfies clause 1 but fails clause 2. A morphism of comodules is a linear map f ⁣:M→Nf \colon M \to N with ρN∘f=(f⊗id⁡C)∘ρM\rho_N \circ f = (f \otimes \id_C) \circ \rho_M.

Reading path

To understand this page from the ground up, read these 5 pages in order. The foundations come first.

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  1. Coalgebra concept
  2. Linear map concept
  3. Tensor product of vector spaces concept
  4. Vector space concept
  5. Comodule definition

Further reading

  1. Web https://en.wikipedia.org/wiki/Comodule
About this page
TagHQTPVQS7TY
URIm2://HQTPVQS7TY
Kinddefinition
WritingW0 stub
MSC16T15
DefinesComodule
UsesCoalgebra, Vector space, Tensor product of vector spaces, Linear map
Changed2 November 2026

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