Math 2.0

Geophysics Definition

Convective available potential energy

Builds on Lapse rate

Definition

Consider a hydrostatic atmosphere with gravitational acceleration gg. Lift an air parcel from near the surface, dry adiabatically up to saturation and then moist adiabatically. Let Tv,p(z)T_{v,p}(z) be the virtual temperature of the parcel and Tv,e(z)T_{v,e}(z) that of the environment at height zz. The level of free convection zfz_f is the lowest height above which the parcel is warmer than the environment, Tv,p>Tv,eT_{v,p} > T_{v,e}. The equilibrium level zn>zfz_n > z_f is the height above zfz_f at which the parcel first becomes as cold as the environment again. The convective available potential energy is CAPE=∫zfzng Tv,p(z)−Tv,e(z)Tv,e(z) dz.\mathrm{CAPE} = \int_{z_f}^{z_n} g \, \frac{T_{v,p}(z) - T_{v,e}(z)}{T_{v,e}(z)} \, dz. If there is no level of free convection, CAPE=0\mathrm{CAPE} = 0.

Remarks

The integrand is the buoyancy acceleration of the parcel, so CAPE has units of J/kg. With the hydrostatic relation and the ideal gas law, CAPE =Rd∫pnpf(Tv,p−Tv,e) dln⁡p= R_d \int_{p_n}^{p_f} (T_{v,p} - T_{v,e}) \, d \ln p, where RdR_d is the gas constant of dry air and pfp_f, pnp_n are the pressures at zfz_f and znz_n. The negative buoyancy below zfz_f gives the convective inhibition.

Example: if Tv,e=300T_{v,e} = 300 K and Tv,p−Tv,e=3T_{v,p} - T_{v,e} = 3 K on the whole layer from zf=1z_f = 1 km to zn=11z_n = 11 km, then CAPE =9.81⋅0.01⋅104≈981= 9.81 \cdot 0.01 \cdot 10^4 \approx 981 J/kg. Parcel theory then bounds the updraught speed by 2 CAPE≈44\sqrt{2 \, \mathrm{CAPE}} \approx 44 m/s.

Non-example: suppose the environmental lapse rate is smaller than the moist adiabatic lapse rate at every level. Then a lifted parcel stays colder than its surroundings, there is no level of free convection, and CAPE is zero.

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Further reading

  1. Web https://en.wikipedia.org/wiki/Convective_available_potential_energy
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DefinesConvective available potential energy
UsesLapse rate
Changed3 November 2026

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