Math 2.0

Functional analysis Definition

Dual pair

Builds on Vector spaceBilinear form

Definition

Let 𝕂\mathbb{K} be ℝ\R or β„‚\C. A dual pair over 𝕂\mathbb{K} is a triple (X,Y,βŸ¨β‹…,β‹…βŸ©)(X, Y, \langle \cdot, \cdot \rangle) such that:

  1. XX and YY are vector spaces over 𝕂\mathbb{K}, and βŸ¨β‹…,β‹…βŸ©β€‰β£:XΓ—Y→𝕂\langle \cdot, \cdot \rangle \colon X \times Y \to \mathbb{K} is a bilinear form.
  2. For every x∈Xx \in X with xβ‰ 0x \ne 0 there is y∈Yy \in Y with ⟨x,yβŸ©β‰ 0\langle x, y \rangle \ne 0.
  3. For every y∈Yy \in Y with yβ‰ 0y \ne 0 there is x∈Xx \in X with ⟨x,yβŸ©β‰ 0\langle x, y \rangle \ne 0.

Remarks

Some authors call any triple satisfying condition 1 a dual pair, and call it separated when 2 and 3 hold. Example: X=Y=ℝnX = Y = \R^n with ⟨x,y⟩=βˆ‘ixiyi\langle x, y \rangle = \sum_i x_i y_i; if xβ‰ 0x \ne 0 then ⟨x,x⟩>0\langle x, x \rangle > 0, which gives 2, and 3 holds in the same way. Example: for a Hausdorff locally convex space EE, the triple (E,Eβ€²,⟨x,f⟩=f(x))(E, E', \langle x, f \rangle = f(x)) is a dual pair; condition 2 follows from the Hahn–Banach theorem, and condition 3 is trivial. Non-example: X=C([0,1])X = C([0, 1]), Y=ℝY = \R, ⟨f,t⟩=tf(0)\langle f, t \rangle = t f(0) satisfies 1 and 3 but not 2, since the function f(s)=sf(s) = s is nonzero and ⟨f,t⟩=0\langle f, t \rangle = 0 for all tt.

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  1. Bilinear form concept
  2. Vector space definition
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Further reading

  1. Web https://en.wikipedia.org/wiki/Dual_system
About this page
TagTVVYHW6FG0
URIm2://TVVYHW6FG0
Kinddefinition
WritingW0 stub
MSC46A20
DefinesDual pair
UsesVector space, Bilinear form
Changed2 November 2026

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