Math 2.0

Operator theory Definition

Graph of an operator

Builds on Unbounded operatorGraph of a functionLinear subspace

Definition

Let XX and YY be normed spaces, and let TT be an unbounded operator from XX to YY with domain D(T)D(T). The graph of TT is the set Γ(T)={(x,Tx):x∈D(T)}⊆X×Y.\Gamma(T) = \set{(x, Tx) : x \in D(T)} \subseteq X \times Y. The product X×YX \times Y carries the norm ∥(x,y)∥=∥x∥+∥y∥\norm{(x, y)} = \norm{x} + \norm{y}, or any equivalent norm.

Remarks

It is the graph of the function T ⁣:D(T)→YT \colon D(T) \to Y. Since TT is linear, Γ(T)\Gamma(T) is a linear subspace of X×YX \times Y.

Example: for X=Y=ℝX = Y = \R and Tx=3xTx = 3x with D(T)=ℝD(T) = \R, the graph is the line {(x,3x):x∈ℝ}\set{(x, 3x) : x \in \R}.

Non-example: the subspace {(0,y):y∈ℝ}\set{(0, y) : y \in \R} of ℝ×ℝ\R \times \R is not the graph of any operator, since it contains (0,1)(0, 1), while every graph contains only (0,0)(0, 0) above x=0x = 0.

A linear subspace GG of X×YX \times Y is the graph of an operator if and only if (0,y)∈G(0, y) \in G implies y=0y = 0. Then D(T)D(T) is the projection of GG onto XX, and TxTx is the unique yy with (x,y)∈G(x, y) \in G. In this way S⊆TS \subseteq T holds exactly when Γ(S)⊆Γ(T)\Gamma(S) \subseteq \Gamma(T).

Reading path

To understand this page from the ground up, read these 4 pages in order. The foundations come first.

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  1. Graph of a function concept
  2. Linear subspace concept
  3. Unbounded operator concept
  4. Graph of an operator definition

Further reading

  1. Web https://en.wikipedia.org/wiki/Unbounded_operator, Definitions and basic properties
About this page
Tag1CF72TCVD2
URIm2://1CF72TCVD2
Kinddefinition
WritingW0 stub
MSC47A05
DefinesGraph of an operator
UsesUnbounded operator, Graph of a function, Linear subspace
Changed2 November 2026

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