Math 2.0

Measure and integration Definition

Haar measure

Builds on Locally compact groupRadon measureBorel sigma-algebra

Definition

Let GG be a locally compact group and let ℬ\mathcal{B} be the σ\sigma-algebra of Borel sets of GG. A left Haar measure on GG is a measure μ\mu on ℬ\mathcal{B} such that:

  1. μ\mu is a Radon measure: it is finite on compact sets, outer regular on Borel sets and inner regular on open sets;
  2. μ\mu is not the zero measure;
  3. μ\mu is left-invariant: μ(gA)=μ(A)\mu(gA) = \mu(A) for every g∈Gg \in G and every A∈ℬA \in \mathcal{B}, where gA={ga:a∈A}gA = \set{ga : a \in A}.

A right Haar measure is defined in the same way with μ(Ag)=μ(A)\mu(Ag) = \mu(A) in clause 3.

Remarks

Example: Lebesgue measure λ\lambda on (ℝn,+)(\R^n, +). It is finite on compact sets, regular and nonzero, and λ(x+A)=λ(A)\lambda(x + A) = \lambda(A) for every x∈ℝnx \in \R^n and Borel set AA.

Non-example: the Dirac measure δ0\delta_0 on (ℝ,+)(\R, +) is a nonzero Radon measure but fails clause 3, since δ0({0})=1\delta_0(\set{0}) = 1 and δ0(1+{0})=δ0({1})=0\delta_0(1 + \set{0}) = \delta_0(\set{1}) = 0.

In integral form, left invariance says ∫Gf(gx) dμ(x)=∫Gf(x) dμ(x)\int_G f(gx) \, d\mu(x) = \int_G f(x) \, d\mu(x) for every g∈Gg \in G and every compactly supported continuous ff. If μ\mu is a left Haar measure, then A↦μ(A−1)A \mapsto \mu(A^{-1}) is a right Haar measure. A left Haar measure gives positive measure to every nonempty open set.

Reading path

To understand this page from the ground up, read these 4 pages in order. The foundations come first.

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  1. Borel sigma-algebra concept
  2. Locally compact group concept
  3. Radon measure concept
  4. Haar measure definition

Further reading

  1. Web https://en.wikipedia.org/wiki/Haar_measure
About this page
TagCE0V9686M8
URIm2://CE0V9686M8
Kinddefinition
WritingW0 stub
MSC28C10, 22D05, 43A05
DefinesHaar measure
UsesLocally compact group, Radon measure, Borel sigma-algebra
Changed2 November 2026

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